-24x^2+14x+5=0

Solution for -24x^2+14x+5=0 equation:

-24x^2+14x+5=0

a = -24; b = 14; c = +5;
Δ = b2-4ac
Δ = 142-4·(-24)·5
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*-24}=\frac{-40}{-48}
=5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*-24}=\frac{12}{-48}
=-1/4
$